Parsing Integers

Question

Though the integer does not satisfy the question it still gives the same output. The code is below: import java.io.Console;

public class TreeStory {

public static void main(String[] args) {
    Console console = System.console();
    /*  Some terms:
        noun - Person, place or thing
        verb - An action
        adjective - A description used to modify or describe a noun
        Enter your amazing code here!
    */
 // --Happy Birthday ---- -----. God --- you and I wish you all the -------- in life"
  String ageAsString = console.readLine("How old are you?: ");
  int age = Integer.parseInt(ageAsString);
  if (age < 13); {
    // Insert exit code
    console.printf("Sorry you must be at least 13 to use this program \n");
    System.exit(0);  
  }
  String name = console.readLine("Enter a name:  ");
  String wish = console.readLine("Enter the wish:  ");
  String emotion = console.readLine("Enter an emotion:  ");

console.printf("Your TreeStory:\n----------\n");
console.printf("Happy Birthday %s  ", name);

console.printf("God %s you and I wish you all the %s in life /n", wish , emotion);

Answer 1 · 2018-01-11T09:41:09Z

January 11, 2018 9:41am

Hi!

You've put a semicolon after the if statement that shouldn't be there.

if (age < 13); {  // <------ this one
    // Insert exit code
    console.printf("Sorry you must be at least 13 to use this program \n");
    System.exit(0);  
  }

Try changing that and see if it works.

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Manisha Gopala

Manisha Gopala

Parsing Integers

1 Answer

Calin Bogdan

Calin Bogdan