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Start your free trialAnastasija Scepak
8,308 PointsParsing Numbers From Strings
I keep getting 12 instead of 10. I am kind of lost
var j = parseInt("012");
2 Answers
Ian Svoboda
16,639 PointsIf you're trying to return 10 from that snippet, you'd need to pass in the radix (8) after your number:
var j = parseInt("012",8);
source: http://www.w3schools.com/jsref/jsref_parseint.asp
Syntax parseInt(string,radix) Parameter Values Parameter Description string Required. The string to be parsed radix Optional. A number (from 2 to 36) that represents the numeral system to be used
Dave McFarland
Treehouse TeacherThere's a teacher's note that was added after the video was created:
Please note that newer browsers will return 12 for parseInt("012") and not 10. This is because the default second parameter is now 10 for decimal instead of 8 for octal. Always specify the base if you're parsing a string to maximize compatibility.
parseInt("012", 10); // For decimal. Returns 12
parseInt("012", 8); //For octal. Returns 10
Anastasija Scepak
8,308 PointsAnastasija Scepak
8,308 PointsThank you for the reply! :)