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Python

Pass the name argument to the template. Print the name variable in the <h1> in the template.

"Didn't find the passed-in name in the template." Please help =)

flask_app.py
from flask import Flask
from flask import render_template

app = Flask(__name__)

@app.route('/hello/<name>')
def hello(name="Treehouse"):
    return render_template("hello.html", name='name')
    return 'Hello {}'.format(name)
templates/hello.html
<!doctype html>
<html>
<head><title>Hello!</title></head>
<body>
<h1>Howdy!</h1>
</body>
</html>

5 Answers

Kenneth Love
STAFF
Kenneth Love
Treehouse Guest Teacher

You don't have a {{ name }} in the template and you're always hardcoding name to the string "name" when you render the template.

This will work, your two errors are, like Kenneth Love said, you used name = 'name' instead of name = name and you didn't put {{name}} in your html template so that value is actually used.

from flask import Flask
from flask import render_template 

app = Flask(__name__)


@app.route('/hello/<name>')
def hello(name="Treehouse"):
    return render_template("hello.html", name = name)
Ruby R
Ruby R
1,086 Points

I got bummer - Dint find the passind-in name in the template.

Code:

from flask import Flask
from flask import render_template

app = Flask(__name__)


@app.route('/hello/<name>')
def hello(name='Treehouse'):
  context={'name':name}
  return render_template("hello.html", **context)
<!doctype html>
<html>
<head><title>Hello {{name}}!</title></head>
<body>
<h1>{{name}}</h1>
</body>
</html>

Michaelangelo,

I haven't taken this course but the web info shows you have to have a placeholder for the incoming variable. It shows something like {{ name }}.

Ron

Right =) I am so used to only editing one file that html escapes my grasp.