Pass value of flavor from the select box

no, if you are posting your form you would do something like this

<form method="POST" action="process.php">
<select name="select">
<option value="option1">Option 1</option>
<option value="option2">Option 2</option>
<option value="option3">Option 3</option>
</select>
<input type="submit" name="go" value="GO" />
</form>

in the php do something like this

<?php

if(isset($_POST['go'])){

$select = $_POST['select'];

echo $select;

}

?>

Have you give your select box a name?

so for example if you had a select box like

<select name="coolbox"> <option value="val1">Option 1</option> <option value="val2">Option 2</option> <option value="val3">Option 3</option> </select>

Then you could get the result in php after you submit the form like so

$select = $_POST['coolbox'];

ok naming the select seems familiar, I need to pass the variable in post right? so I have input=submit action="process.php?flavor=NAMEOFSELECT>

Shane,

If you want the selection to be appended to the end of the URL, you will need to switch the form method from post to get. Get will send all the form information via the URL. Post will send all form information in the background and not in the URL. If you need the form information in the URL, switch the form method to GET.

Cheers!