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JavaScript

Posted by Ayaz Sadiq
Ayaz Sadiq
Courses Plus Student 5,361 Points

Passing an argument into a function

Can someone please tell me what is wrong with my code. My code will not run.

function returnValue(food) { return food }

var echo { return food alert(returnValue); }

2 Answers

Cindy Lea
PLUS
Cindy Lea
Courses Plus Student 6,497 Points
Cindy Lea
Cindy Lea
Courses Plus Student 6,497 Points

I believe your last statement is wrong. You need to store the value returned from the function in a variable then use echo to display it. Youre trying to call the function again in the echo.

Craig Watson
Craig Watson
27,930 Points
Craig Watson
Craig Watson
27,930 Points

Hi,

best way to explain is with some code so below is a small example.

var checkFood = function(){
    var favFood = prompt("What is your favourite food?").toLowerCase();
    if ( favFood != "icecream" ) {
        alert("Why didn't you choose icecream?");
    } else {
        alert("Mine to!");
    }
};
checkFood();

First thing we do is create the variable to store the function in, inside that we then we create the prompt to get the value and store that in a separate variable. Now we have the result we can run the test to see if they like icecream just as much as I do and "alert" them to how I feel about their choice.

hope this helps craig