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JavaScript Object-Oriented JavaScript Getters and Setters Object Interaction

Tsipporah Christopher
.a{fill-rule:evenodd;}techdegree seal-36
Tsipporah Christopher
Full Stack JavaScript Techdegree Graduate 15,593 Points

phone.replace() doesn't work, and when I try to return the phone it comes back undefined

Hello I am having trouble getting the replace property to work. And later when I try to directly call the phone property it returns undefined. Thank you!

class Pet {
    constructor(animal, age, breed, sound) {
      this.animal = animal;
      this.age = age;
      this.breed = breed;
      this.sound = sound;

    get activity() {
    const today = new Date(); 
    const hour = today.getHours(); 

    if (hour > 8 && hour <=20) {
      return 'playing';
    } else {
      return 'sleeping';


    get location() {
    const today = new Date(); 
    const day = today.getDay(); 

    if (day == 0) {
      return 'outside';
    } else {
      return 'in the backyard';


    get owner() { 
    return this._owner;   

    set owner(owner) { 
      this._owner = owner; 

    speak() {


class Owner {
    constructor (name, address) {
        this.name = name;
        this.address = address;

    set phone(phone) {
        const phoneNumber = phone.replace(/[^\d]/g, '');
        this._phone = phoneNumber;

    get phone() {
        return this._phone;


const golden = new Pet('dog', 1, 'pug', 'bow wow');
const charm = new Pet('dog', 8, 'border collie' , 'woof woof');

golden.owner = new Owner('Isis', '123 main street');

golden.owner.phoneNumber = '(123) 456-7890';




1 Answer

Steven Parker
Steven Parker
228,025 Points

The phone.replace() code looks good, but it isn't being used here. The setter code only runs when you assign something to the phone property, but the later code is creating a new property named "phoneNumber" instead.

That's also why the getter for phone returns "undefined", as the backing value has never been created.