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Ross Finn
5,292 Pointsphp basics, conditionals and loops, can;t figure this out, watched the video a dozen times.
<?php
$name = "Mike";
$info = "Hi, I am Mike!";
if($name == 'Mike'){
echo = "Hi, I am Mike!";
}
?>
I can't figure this one out. This what I've come up with. Anyone any ideas?
3 Answers
Ethan Lowry
Courses Plus Student 7,323 PointsYou shouldn't have the equals sign after echo - you're not assigning anything to echo, you're calling the echo function and passing it a string. Thus that section of the code should just be:
if($name == 'Mike'){ echo "Hi, I am Mike!"; }
But that's not all - remember we use variables for a reason: to allow for easy reuse of code. Look for somewhere in your code that you're writing something twice when you could be using your variable/s instead. :)
If you want, you can find some further explanation of echo here.
Michael Hulet
47,912 PointsI notice one problem with your code right off the bat. You have an = between echo and "Hi, I am Mike!" in your if statement, as if echo is a variable. With commands in PHP, you shouldn't put an = between the command and any of its parameters. Also, you assigned $info to that string value for a reason. See if this works:
<?php
$name = "Mike";
$info = "Hi, I am Mike!";
if($name == 'Mike'){
echo $info;
}
?>
Also, I prettified your code to make it easier to read. To learn how to do this yourself, check out the Markdown Cheatsheet, under the box where you'd type a reply
Ross Finn
5,292 PointsAgh! What was I thinking. Silly mistake. Thanks guys.