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Start your free trialGIFT AKARIS
4,383 PointsPHP BUILD BASIC QUESTION ON CONDITIONALS NOT CLEAR ENOUGH
The message in the final echo command only makes sense if your favorite flavor is the same as Hal's. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.
Hi Everyone,
Am finding it hard to understand this question, I need help please
<?php
$flavor= 'Biscuit';
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
echo $flavor;
?>
1 Answer
scribbles
21,173 PointsThe fourth echo statement has a hard-coded message of "<p>Hal's favorite flavor is cookie dough, also!</p>", and in the example you posted the favorite flavor is "Biscuit" as evidenced by this line:
<?php
$flavor= 'Biscuit';
So, right now in this code it doesn't matter what is stored in the $flavor variable it will echo "<p>Hal's favorite flavor is cookie dough, also!</p>" anyway. This wouldn't make much sense if someone's favorite flavor is "Biscuit".
The challenge wants you to add a conditional statement that will check to see if $flavor == "cookie dough" and if it is then (and only then) you should echo that statement. Something like this should work:
<?php
$flavor= 'Biscuit';
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == 'cookie dough') {
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
}
echo $flavor;
?>