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PHP Challenge Problem

Next, we need the flavor selected in the dropdown to be submitted to this process.php file. We need to be able to access it in the “flavor” element of the $_POST array like this: $_POST["flavor"]. What two changes do we need to make to the HTML? (Hint. We need to add two new attributes. The first needs to be added to one existing HTML element, the second needs to be added to a different existing HTML element.)

I can't quite figure either of these out. Can someone show me an example or help me solve this. I read the "Bummer" statement but I've been stuck for days!

<!DOCTYPE html> <html> <head> <title>Ye Olde Ice Cream Shoppe</title> </head> <body>

<p>Your order has been created. What flavor of ice cream would you like to add to it?</p>

<form action="process.php" method="POST">

    <label for="flavor">Flavor</label>
    <select id="flavor" name="$flavor">
        <option value="">&#8212; Select &#8212;</option>
        <option value="Vanilla">Vanilla</option>
        <option value="Chocolate">Chocolate</option>
        <option value="Strawberry">Strawberry</option>
        <option value="Cookie Dough">Cookie Dough</option>

    <input type="submit" value="Update Order">


</body> </html>

5 Answers

Randy Hoyt
Randy Hoyt
Treehouse Guest Teacher

You are very close. The name should be flavor, like this:

<select id="flavor" name="flavor">

You have set it to $flavor with a dollar sign. The dollar sign is only used before PHP variables.

Does that help?

5,912 Points

I'm stuck on this one, I can't see what I'm doing wrong, as it's coming up OK on the right hand side!

Q. If the array is NOT empty, the foreach loop will execute. But if it IS empty, we should display a message. Add an else block to the conditional that displays the following message in an HTML paragraph tag: 'There are no flavor recommendations for you.'

A. <?php

 $recommendations = array();


<h1>Flavor Recommendations</h1>

if (!empty($recommendations)){ 
echo "<ul>";
foreach($recommendations as $flavor) {
echo "<li>" . $flavor . "</li>";
echo "</ul>";
else {
echo '<p>There are no flavor recommendations for you.</p>';

error message: Bummer! The array is empty, but I don't see the message indicating that no flavors are found.

Scott Bedard
Scott Bedard
29,196 Points

i am having the same issue. I know the code is correct, but it is not showing anything and just keeps saying it is incorrect.

John Coughlan
John Coughlan
9,414 Points

I had trouble with this one, too. Maybe your problem is with the concatenation this line?

echo "<li>" . $flavor . "</li>";

here's the code that worked for me:

<?php if (!empty($recommendations)) { echo "<ul>"; foreach($recommendations as $flavor) { echo "<li>"; echo $flavor; echo "</li>"; } echo "<ul>"; } else {echo "<p>There are no flavor recommendations for you.</p>";} ?>

good luck!