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PHP

Edward campbell malan van wyk
Edward campbell malan van wyk
6,403 Points

PHP file upload

I have a basic form to upload files to my web server.

<form enctype="multipart/form-data" action="" method="post"> Browse for File to upload: <br> <input name="UploadFileField" type="file" id="UploadFileField"><br> <button onClick="getFilePath();" type="button" id="UploadButton" name="upload_button" value="Upload the File" style="width:100px; height:auto">Upload File</button> </form>

The following function posts the filepath to a php script.

function getFilePath() { var filepath = $('#filePath').text(); $.post("assets/php/uploadFile.php", {filepath:filepath}, function(result){alert(result)});
}

In the php file i check if a file is selected to be uploaded then i create the necessary variables needed to upload a file.

if(isset($_FILES['UploadFileField'])) { $UploadName = $_FILES['UploadFileField']['name']; $UploadTmp = $_FILES['UploadFileField']['tmp_name']; $UploadType = $_FIles['UploadFileField']['type'];

Finaly my question, the php script is a separate file. thus it does not see the 'UploadFileField' name that is given to the input tag in a different script.

How can I let the php script with my upload php see this input tags name? or am I being stupid about this....

:/

TIA

1 Answer

Konrad Traczyk
Konrad Traczyk
22,287 Points

Hi Edward,

TBH i dont understand why you're using ajax for this?

If you'd like to pass file to other script file you place the filepath in forms tag action attribute. Like this:

<form action="assets/php/uploadFile.php" method="post" enctype="multipart/form-data">
    Select image to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>

If this doesnt convince you i suggest you to ask google about "file upload through AJAX".

PS. In jQuery we don't use .text() to get value from input you should use .val() function