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MIHA W.LEE
PHP Development Techdegree Graduate 25,452 PointsPHP foreach
$numbers = array(1,2,3,4); $total = count($numbers); $sum = 0; $loop = 0;
foreach($numbers as $number) { $loop = $loop + 1; if ($loop < $total) { $sum = $sum + $number; } }
echo $sum;
I just took the quiz right here, I think the result should be 10, but why the result is 6?
Hope someone can tell me the detail, thank you so much!
MIHA W.LEE
PHP Development Techdegree Graduate 25,452 PointsThank you for your help. So, what if there is no $loop variable at here, then there is only one value will pass to the $sum variable?
Justin Barrett
27,345 PointsJustin Barrett
27,345 Pointsin your pass: //first pass, loop = 1, if(1 < 4){sum = 0 + 1}, sum = 1 //second pass loop = 2, if(2 < 4) {sum = 2+2;}, sum = 3 //third pass loop = 3, if(3 < 4), {sum = 3+3;}, sum = 6 //fourth pass loop = 4, if(4 < 4), false, sum still equals 6
if you were to change to if ($loop <= $total), then the fourth pass would be true and your sum would equal 10.
//revised fourth pass loop = 4, if(4 <= 4), {sum = 6+4;}, sum = 10