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PHP

Posted by Darius Strong
Darius Strong
3,956 Points

PHP & MYSQL Chrome not recognizing try code??

<?php

try{ $db = new PDO("mysql:host=localhost;dbname=shirts4mike;port=8889","root","root"); $db->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION); $db->exec("SET NAMES 'utf8'"); } catch (Exception $e) { echo "Could not connect to the database."; exit; }

try{ $results = $db->query("SELECT name, price FROM products"); echo "Our query ran successfully."; } catch (Exception $e){ echo "Data could not be retrieved." exit; }

?>

it does not echo ANYTHING.

Am i doing something wrong?

1 Answer

ryanloerzel
ryanloerzel
12,671 Points
ryanloerzel
ryanloerzel
12,671 Points

Have you tried adding an echo statement to your first try block? Your second catch statement is missing a semicolon after "retrieved." I tried your code and received a parse error message from that missing semicolon. This worked on my machine (I changed the port number and excluded the password parameter.) I'm using Easy PHP server and MySQL Workbench.

   <?php
        try{
             $db = new PDO("mysql: host = localhost; dbname=shirts4mike; port=3306",               
                 "root"); 
            $db->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION); 
            $db->exec("SET NAMES 'utf8'"); 
            echo "Connected to database."; 
       } catch (Exception $e) { 
            echo "Could not connect to the database."; 
            exit; 
      }

    try{ 
           $results = $db->query("SELECT name, price FROM products"); 
           echo " Our query ran successfully."; 
    } catch (Exception $e){ 
            echo "Data could not be retrieved.";
            exit; 
   }
   ?>

OUTPUT: Connected to database. Our query ran successfully.

Darius Strong
Darius Strong
3,956 Points

thanks