Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Build a Simple PHP Application Wrapping Up The Project Objects

PHP Objects Challenge Task 4

I am really confused as to this question, and cannot get past it. I need to assign the property (numbers) of PalprimeChecker a value of seventeen, and I cannot pass the stage.



$checker = new PalprimeChecker(
$checker["number"] => 17;

echo "The number " . $checker["number"] ;
echo "(is|is not)";
echo " a palprime.";


1 Answer

Erik McClintock
Erik McClintock
45,783 Points


This can definitely be a tricky task, but it seems it may best suit you to go back and rewatch some videos to try and make sure you've got placement and syntax for things down. In the meantime, here are the errors in your code:

1) Do not place your property assignment inside of the parenthesis of the PalprimeChecker, and make sure you close your statement with a semi-colon

You have:

$checker = new PalprimeChecker(
    $checker["number"] => 17; // this is inside of PalprimeChecker - we don't want that
) // no semi-colon present - we don't want that

You need:

$checker = new PalprimeChecker(); // semi-colon present

$checker["number"] => 17; // assignment outside of PalprimeChecker

2) To access properties on an object in PHP, use the single arrow ( -> ) character, and then an equals sign ( = ) to assign it a value

You have:

$checker["number"] => 17;

You want:

// note the -> character to access the number property of the $checker object, and the = to assign the value
$checker->number = 17;

3) Make sure you use the -> syntax in your echo statement, as well, and then concatenate another space character after it

You have:

echo "The number " . $checker["number"] ;

You want:

echo "The number " . $checker->number . " ";


Thank you so much. It worked!