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Andy Christie
1,361 PointsPlease can you help me with this python challenge
This challenge says where is sillycase() as an error message. please can someone tell me what's wrong.
# The first half of the string, rounded with round(), should be lowercased.
# The second half should be uppercased.
# E.g. "Treehouse" should come back as "treeHOUSE"
def sillycase (Treehouse):
leng = (len(Treehouse) / 2)
first = silly[:leng].round()
second = silly[leng:]()
return first + second
2 Answers
Robert Richey
Courses Plus Student 16,352 PointsHi Andy,
That's a really good attempt! You understand the general solution. We just need to fix some syntax and relocate the round() function.
First, let's tackle round(). Without it, when calling len() on a string with an odd number of letters, it will return a floating point value.
len("apple") / 2
# equals 2.5
# In order to round this value, we can put this expression
# inside the round function.
round(len("apple") / 2)
# equals 2
# Your variable is called leng, but really it's holding half the length.
# Perhaps consider renaming it to half.
Next up is slicing the string. Your code is trying to slice a string inside a undefined variable silly. Your method is accepting a variable called Treehouse, so you can either change the variable name being sliced to Treehouse or change the parameter of the method to silly - either way will work.
Finally, change the first half of the string to lowercase and the last half to uppercase.
"apple".upper() # equals "APPLE"
"TOMATO".lower() # equals "tomato"
# we can chain methods after slicing like this
Treehouse[:half].lower()
# the string inside the variable name Treehouse will be sliced from index 0
# up to but excluding index half and then lowercased.
Hope this helps,
Cheers
Andy Christie
1,361 PointsHi thankyou for the good feedback and help. It passed I did it a bit different I just needed the round function in the leng variable.