Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Python Web Development Techdegree Student 1,270 Points

please help in making the dictionary

cant turn the text into a dictionary with their counts

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(st):
    for c in b:
        return(c, b.count(c))

2 Answers

Hi Alex,

I started this by creating an output dictionary that was empty. I called it output. Next, I took the incoming parameter (I called it in_string; you've called it st), made it lowercase, split it using split() and assigned that into a new variable which I called string.

Next, I created a for loop to iterate over the words in string. At each iteration I tested, using if whether the iterator (I called it word) was already contained in output. If it is there already, I incremented output[word] by 1. If it isn't already in output I set output[word] to be equal to 1.

At the end of the for loop, I returned the output dictionary.

Let me know how you get on.


:+1: :+1: