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Python Python Basics (2015) Shopping List App Break

Asad Malgi
Asad Malgi
641 Points
Posted by Asad Malgi
Asad Malgi
641 Points

Please help in this Python task?

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code! Its a Python task. Please help me out through examples. Please!

breaks.py 
def loopy(items):
    # Code goes here
    buy = ['cat', 'mat', 'rat','STOP']
    for items in buy:
        if items == 'STOP':
        break
    buy.append(items)
    for a in buy:
        print(a)

3 Answers

Emre Havan
Emre Havan
8,569 Points
Emre Havan
Emre Havan
8,569 Points

You dont need to create "buy" or anything like that for this task. You dont need to use .append method either. You can simple get both tasks done with the codes given below: 

def loopy(items):
    for i in items:
        if i == "STOP":
            break
        else:
            print(i)
Asad Malgi
Asad Malgi
641 Points
Asad Malgi
Asad Malgi
641 Points

I am sorry bro! not working!

Jing Huang
Jing Huang
1,634 Points
Jing Huang
Jing Huang
1,634 Points

def loopy(items): # Code goes here for items in buy: if items == 'STOP': break print(items)

You don't need two for loops and append.

Asad Malgi
Asad Malgi
641 Points
Asad Malgi
Asad Malgi
641 Points

sorry bro! not working!

Asad Malgi
Asad Malgi
641 Points
Asad Malgi
Asad Malgi
641 Points

Please somebody help me!

Jing Huang
Jing Huang
1,634 Points

uhm, try the code below. 

def loopy(items):
    for item in items:
        if item == "STOP":
            break
        print (item)