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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Posted by channonhall
channonhall
12,247 Points

Please help me

Challenge task 2 of 4 I'm not too sure how to do this Please help me guys

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if(xhr.readyState === 4) {
    if(xhr.status === 4w){
    }
  }  
document.getElementById('sidebar').innerHTML = ?
};
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

1 Answer

Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

this seems to work for part 2:

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
 if(xhr.readyState === 4 && xhr.status === 200) {
 }
};
xhr.open('GET', 'sidebar.html');
xhr.send();
Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

the challenge seems to have faulty verification on the status attribute. So the initial post i made was faulty. I've corrected the above to use the status attribute.

channonhall
channonhall
12,247 Points

Thank you Soo much Simon I allready got it but anyways thanks for helping I made you best answer Thank you Again Simon.