Please how to re-count binary into decimal numeric system. equation would be more than welcome. Thank you

Basically, the digit all the way to the right has a value of 1. The next digit to the left has a value of 2. The next has a value of 4. The next has a value of 8.

And they keep doubling in value as you continue to add digits.

In your example, 00000001 means you have: (0 x 128) + (0 x 64) + (0 x 32) + (0 x 16) + (0 x 8) + (0 x 4) + (0 x 2) + (1 x 1) = 1

For another example, if you wanted to represent the number 135 in binary...you would need 128 + 4 + 2 + 1: (1 x 128) + (0 x 64) + (0 x 32) + (0 x 16) + (0 x 8) + (1 x 4) + (1 x 2) + (1 x 1) = 10000111

Well let's take 1001001 for example:

We start at the right and work left. And we only look at the ones. I'm using the ^ character here to denote to the power of. For example 3^4 is equal to 81.

2^0 = 1 then we add 2^3 = 8 then we add 2^6 = 64

This gives us a total of 73. So the decimal value for 1001001 is equal to 73. Hope this helps!

you are supper nice Thank you for finding time to answer my questiion. Now I reallyl got it once more thank both of you very much