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omri luz
5,148 PointsPlease tell me what is wrong with my code
i have no idea what i am doing wrong
import random
start = 5
while start == 5:
def even_odd(num):
num = random.randint(1, 99)
if num % 2 == 0:
print ("{} is even".format(num))
else:
print("{} is odd".format(num))
start -= 1
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
1 Answer

Robert Ionut Muraru
Full Stack JavaScript Techdegree Graduate 22,194 PointsHello,
You are defining the even_odd() function within the while loop which is not necessary. You should use the even_odd() function inside the while loop to check if a number is even or not. Try writing the code again, you can leave the definition of the even_odd() function as it is and just create the while loop under it:
import random
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
# here is how you could think about the remaining challenge:
'''while start is not falsey:
declare a variable and assign to it the value you get using random.randint(1, 99)
if that variable is even:
print "{} is even",putting the random number in the hole
else:
print "{} is odd", again using the random number
decrement start by 1
'''
Hope it helps you.
nakalkucing
12,964 Pointsnakalkucing
12,964 PointsWhat error are you getting?