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Python Python Basics (2015) Letter Game App Even or Odd Loop

omri luz
omri luz
5,148 Points
Posted by omri luz
omri luz
5,148 Points

Please tell me what is wrong with my code

i have no idea what i am doing wrong

even.py 
import random
start = 5
while start == 5:
    def even_odd(num):
        num = random.randint(1, 99)
        if num % 2 == 0:
            print ("{} is even".format(num))
        else:
            print("{} is odd".format(num))
        start -= 1
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
        return not num % 2
nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

What error are you getting?

1 Answer

Robert Ionut Muraru
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PLUS
.a{fill-rule:evenodd;}techdegree seal-36
Robert Ionut Muraru
Full Stack JavaScript Techdegree Graduate 22,194 Points
Robert Ionut Muraru
.a{fill-rule:evenodd;}techdegree seal-36
Robert Ionut Muraru
Full Stack JavaScript Techdegree Graduate 22,194 Points

Hello,

You are defining the even_odd() function within the while loop which is not necessary. You should use the even_odd() function inside the while loop to check if a number is even or not. Try writing the code again, you can leave the definition of the even_odd() function as it is and just create the while loop under it:

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5

# here is how you could think about the remaining challenge:

'''while start is not falsey:
    declare a variable and assign to it the value you get using random.randint(1, 99)
    if that variable is even:
      print "{} is even",putting the random number in the hole
    else:
      print "{} is odd", again using the random number
    decrement start by 1 
'''

Hope it helps you.