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# pls help

Pls help with the code,

1. why this code is wrong
2. how can we do in one step using insert and pop

lists.py
```messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
for i in range(1,4):
del messy_list[0]
```

Looks like that your code indentation is with more than 4 spaces on row 3.

You are also doing a range from (1,4), getting only the values [2, 3, 1] of your array, remember, an array starts with index 0, and when you do a range from x to y, you are getting the content of index x to (y-1), in this case (1 to 3), resulting in the values 2,3,1.

If you only want to remove the first value of your array, you can do this in some ways:

`messy_list.pop(0)` or `del messy_list[0]`

Cheers, Felipe

the insert method can insert a specific item at any index at the array. Here is how it works:

```array = [2, 3, 5]
array.insert(0,1) # This will insert the int 1 at index 0
array.insert(3, 4) # This will insert the int 4 at index 3
print(array) # This will print out [1, 2, 3, 4, 5]
```

With that said, you can insert an item you just poped from the array using this statement:

```array.insert(0, array.pop(2)) # This will insert the item poped from index 2 back at index 0
```

So, applying it to your code, you can do it in one statement like this:

```messy_list.insert(0, messy_list.pop(3))
```

After that, you have to remove the string (wich is more like a char), the boolean and the list from the messy_list. You can remove items from a list using .remove(). So, to complete this task, you can remove all that from the list using:

```messy_list.remove('a')
messy_list.remove(False)
messy_list.remove([1, 2, 3])
```