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Python Python Basics (2015) Number Game App Even or Odd

Oscar Chong
PLUS
Oscar Chong
Courses Plus Student 292 Points
Posted by Oscar Chong
Oscar Chong
Courses Plus Student 292 Points

Pls help me out

the question is :

Write a function named even_odd that takes a single argument, a number.

return True if the number is even, or False if the number is odd.

You can use % 2 to find out the remainder when dividing a number by 2. Even numbers won't have a remainder..

Can you pls tell me what should i do? Thanksss

even.py 
def even_odd(num):
    while True:
        if num == even:
            return True
        else:
            return False

1 Answer

Oli Flemmer
Oli Flemmer
13,394 Points
Oli Flemmer
Oli Flemmer
13,394 Points

You need to use % to find out if a number is odd or even. What % does is find the remainder of a division calculation; for example 9 % 4 = 1 . This is because 9 divided by 4 is 2 REMAINDER 1. All even numbers % 2 = 0. And all odd numbers % 2 = 1. E.g 6% 2 = 0 and 5 % 2 = 1. You can wright an if statement to check if num % 2 = 0 or 1. If it’s 0 then it’s even and you can return False if it’s 1 then you can return True.

Try and attempt to do the chanllenge on your own, but I’m going to leave my code below.

def even_odd(num):
    if num % 2 == 0:     #even
        return False
    if num % 2 == 1:    #odd
        return True