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# Plz tell how to do this

Plz send me the correct code to solve this problem

disemvowel.py
```def disemvowel(word):
return word
vowel = ["a" , "i", "e","o","u"]
try:
word.remove(vowel)
except ValueError:
pass
```

Hello Ashmit,

You seem a little lost.

• All of the code you write should be within the `disemvowel` function.
• You cannot remove `vowel` from `word`, as `word` does not contain a list (it's a string!).
• You do not need a try/except block for this problem.

Unfortunately, as I have stated, you cannot remove an array from a string. It simply doesn't make sense. Moreover, even if you remove a single character from a string, it only would remove the first find for that character, it wouldn't remove all finds.

This means you must iterate through the string, and if the character you're on isn't in the string `"aeiou"`, then you may append the character to the result string which you will return.

Here's the code, but please do not copy and paste the code, just understand how it works. Trust me, if you type it out on your own, you will learn programming much better.

```def disemvowel(word):
result = ''
for i in word:
if i not in "aeiouAEIOU":
result += i
return result
```

Happy coding! ~Alex

UPDATED DUE TO MISTAKE IN CODE

sir why have to take this step result += i in the code plz explain

`result += i` appends `i` to the end of the string `result`.

For example...

(Pretend I'm in the Python Shell.)

```>>> foobar = 'foo'
>>> foobar
'foo'
>>> foobar += 'bar'
>>> foobar
'foobar'
>>>
```

It's actually a shorthand for this:

```result = result + i
```

And, as you may know, `result` and `i` are both strings, and in Python, when you add two strings together, it "glues" them together.

I hope this helps