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Enzie Riddle
Front End Web Development Techdegree Graduate 19,278 Points.pop() and .insert()
Here's the question:
Alright, my list is messy! Help me clean it up! First, start by moving the 1 from index 3 to index 0. Try to do this in a single step by using both .pop() and .insert(). It's OK if it takes you more than one step, though!
What am I doing wrong? PLEASE explain in a way that is easy to understand: I am new to this!
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
value_1 = messy_list.pop(3)
value_1.insert(0)
3 Answers
Steven Parker
231,269 PointsYou're halfway there.
Your pop is fine, you remove the item at index 3 and capture the value in your variable "value_1 ".
But when you insert you have the method attached to your variable instead of the list. And insert requires two arguments, the position (which you have correctly as 0), but it also needs the value to insert (your variable).
Ari Misha
19,323 PointsAlright! Try this:
messy_list.insert(0, (messy_list.pop(3)))
Since pop() function removes the last indexed object from your list , we can use the object returned by our pop() function and pass it to insert() function which takes two arguments: Index and object. So yeah we could use the returned object by pop() function and pass it to insert(). Hope that helped (:
f4u57
6,743 Pointsmessy_list.insert(0,messy_list.pop(3))