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PHP

Łukasz Czuliński
Łukasz Czuliński
8,646 Points
Posted by Łukasz Czuliński
Łukasz Czuliński
8,646 Points

Prepared statement only returning 1 array (should be more).

I've run into a problem while learning about prepared statements.

When I run this:

try{
    $conn = new PDO('mysql:host=localhost;dbname=adfm', $user, $pass);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    $stmt = $conn->prepare('SELECT*FROM users WHERE location = :place');
    $stmt->bindParam('place', $location, PDO::PARAM_STR);
    $stmt->execute();

    while ($row = $stmt->fetch()) {
        print_r($stmt->fetch());  
    }

} catch(PDOException $e){
    echo 'ERROR: ' . $e->getMessage();
}

The above code only returns one array. But when I do the identical query in my MySQL client like: 

SELECT*FROM users WHERE location = 'Kuala Lumpur';

It returns all pertaining rows/arrays correctly. Am I doing something wrong in the prepared statement?

1 Answer

Łukasz Czuliński
Łukasz Czuliński
8,646 Points
Łukasz Czuliński
Łukasz Czuliński
8,646 Points

Worked it out.

This statement was causing the problems:

    while ($row = $stmt->fetch()) {
        print_r($stmt->fetch());  
    }

Not sure how I ended up with that since it makes no sense.

I corrected it to:

    while ($row = $stmt->fetch()) {
        print_r($row);  
    }