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Renee Leslie
Courses Plus Student 299 PointsPrint function is giving me an error "size of" for array length
float real_numbers[] = {1,2,3,4,5}; printf("float %ld bytes\n" , size of (float));
it gives me an error that "size" is not declared. I don't understand. I took notes and that's how I was taught.
2 Answers
Jason Anello
Courses Plus Student 94,610 PointsHi Renee,
You have a few errors with your code. sizeof shouldn't have a space in it.
Also, it's asking for the size of real_numbers not the size of a float. real_numbers is an array with enough space for 5 floats. So really what they're asking is what's the size of 5 floats.
One more thing is that your output string wouldn't match what it's asking for.
The output string should be in the form Array real_numbers is x bytes.
Your current output string looks like float x bytes\n
Let us know if you're still stuck.
Renee Leslie
Courses Plus Student 299 PointsThank you Jason for your insight. I did have a space between size of, so I corrected it to "sizeof" and it worked. The little things make a big difference when writing a code!
I appreciate your assistance! I'm new to Treehouse, so I apologize for not responding to your answer.
Jason Anello
Courses Plus Student 94,610 PointsJason Anello
Courses Plus Student 94,610 PointsForgot to mention too that you don't have to initialize your array with 5 values. You only have to declare an array that will hold 5 values.
Putting in 5 numbers still passes but this will work too:
float real_numbers[5];