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Python Conditional Check

Posted by Murilo de Melo
Murilo de Melo
14,456 Points

print(__name__) in second_app.py prints out '__main__'. Why?

Because the print( __ name __ ) is outside a check in app.py it is run in second_app.py, and therefore it outputs ' __ main __ ' for app.py and 'app' for second_app.py. I inserted on purpose another print( __ name __ ) to second_app.py , right under the statement print("Hello from second_app.py"). The output for this new statement was ' __ main __ '. Since this is an import file and not app, why does it put out ' __ main __ ' instead of two times 'app'?

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I'm not sure I understand your description. Can you provide a link to a snapshot of your workspace?

Murilo de Melo
Murilo de Melo
14,456 Points

https://w.trhou.se/q7vmy19z7p

Inserting print( __ name __ ) also in the script second_app.py, it outputs '__ main __' instead of 'app'

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

So "second_app.py" is your main program (the one you run), and it imports "app". Perhaps it would help in understanding the output if we look at where each line of the output comes from:

Output Where It Comes From
workspace$ python second_app.py typed in to run the program
app line 4 of app.py ("print(__name__)")
Hello from second_app. line 3 of second_app.py
__main__ line 5 of second_app.py ("print(__name__)")
Hello from app. line 2 of app.py

So you can see that only the program that you run prints out "__main__" as the name. The imported one prints out the name of the file instead.

Murilo de Melo
Murilo de Melo
14,456 Points

Oh I see. It is a little confusing but now it makes sense for me. Thank you Steven :)