Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
khuong tran
Courses Plus Student 7,064 Pointsproblem with understanding php Quiz - section : working with function
What does the following code display? <?php
$numbers = array(1,2,3,4);
$total = count($numbers);
$sum = 0;
$output = "";
$i = 0;
foreach($numbers as $number) {
$i = $i + 1;
if ($i < $total) {
$output = $number . $output;
}
}
echo $output;
?>
Can anyone explain how this piece of code echo out "321" instead of "123"
2 Answers
Petros Sordinas
16,181 PointsThe $output = $number . $output; statement prepends each number to the output string, i.e.
In the first foreach cycle, $output = "1" ($number = 1, $output = "")
In the second, $output = "21" ($number = 2, $output ="1")
In the third, $output = "321" ($number = 3, $output = "21") etc
To echo 123, the statement should have been $output = $output . $number;
khuong tran
Courses Plus Student 7,064 PointsThanks so much now I get it .