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PHP PHP Basics Daily Exercise Program Daily Exercise Program

Jason Brown
Jason Brown
9,626 Points
Posted by Jason Brown
Jason Brown
9,626 Points

Program always returns today's date, no matter how many times I change the $day variable ...

I can't get this program to return anything but today's date. Please help! : "" <?php // Store each exercise in a string variable. $exercise1 = "this"; $exercise2 = "isnt"; $exercise3 = "working"; $exercise4 = "i"; $exercise5 = "want"; $exercise6 = "it"; $exercise7 = "to work";

$day = date('N');

if ($day == 1) { echo $exercise1; } elseif ($day == 2) { echo $exercise2; } elseif ($day == 3) { echo $exercise3; } elseif ($day == 4) { echo $exercise4; } elseif ($day == 5) { echo $exercise5; } elseif ($day == 6) { echo $exercise6; } else { echo $exercise7; } $day = 3; $day = date(2);

// create a variable containing the day of the week. // Use if statement to test for the day of the week. // display corresponding exercise string.

$day = 1; $day = 1; ?> ""

1 Answer

Eric Butler
Eric Butler
33,512 Points

Hey Jason, You need to move your different $day declarations up above the if block, because right now the only $day value being fed into all your if statements is the one above it, which is $day = date('N');. If you moved your $day = 3 or $day = 1 statements up so they're just underneath your $day = date('N') statement, you'd echo different outputs as desired.

Hope this helps!

Jason Brown
Jason Brown
9,626 Points
Jason Brown
Jason Brown
9,626 Points

Gah! Of course! I wouldn't do this if I was actually writing a program ... I just wasn't thinking about that because I was fooling around in workspaces. Ohhh boy ... Thanks so much for your response. A valuable lesson learned, either way. Thanks again.