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Java Java Basics Perfecting the Prototype Conditional ints

Posted by Ezekiel Elin
Ezekiel Elin
3,839 Points

Program Variable Name Isn't Working

Conditional.java 
Integer numberOfPeople = 3;

Bummer! Make sure you create an int with the name of numberOfPeople with a value set to 3.

Michael Skutt
Michael Skutt
7,442 Points

Try

int numberOfPeople = 3;

"int" is a primitive type, while "Integer" is a class

1 Answer

Rob Bridges
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Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points
Rob Bridges
.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points

Hey Ezekiel,

It looks the confusion Java is running into is the integer is "int" in java for the primitive type.

So this should look something like like

int numberOfPeople = 3;

Thanks let me know if this doesn't help.