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Jacob Lewis
17,355 PointsPython Collections: Lists Redux Quiz
The code challenge asks you to move the '1' to position 0. It also says you can do it in one step with .pop() and .insert(). I couldn't solve it in one step and, I did it this way:
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
Your code goes below here
neo=the_list.pop(3)
new_list=the_list.insert(0, neo)
Can someone show me how to solve it in one step?
7 Answers
Cody Te Awa
8,820 PointsSince the .pop() method removes and also returns a value from a list, you can chuck it inside the insert statement. the insert statement is expecting a index and a value to insert at the given index. so if you were to have something like this: the_list.insert(0, the_list.pop(3)) we are popping the index 3 which is of value 1 and at the same time returning it to the insert method to therefore place it in the index 0. -Hope that helps!
ellie adam
26,377 Pointsthe_list = ["a", 2, 3, 1, False, [1, 2, 3]]
the_list.pop(3)
the_list.insert(0, 1)
Jacob Lewis
17,355 PointsThat did help solve it. Thanks, Cody.
Charles Steinmetz
14,420 PointsYou need to pop the value by it's index number and store this in a variable. Then insert that new variable into the proper position. I did it this way:
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
a_list = the_list.pop(3)
the_list.insert(0, a_list)
Tony McCabe
4,889 PointsTreehouse.com is fun, but they need to take some English course... They should of said place a new variable, then place either .pop, or .insert() The code you would place is same as Charles Steinmetz. He has the answer.
Joshua Eagle
9,778 PointsThis is old, but I was searching this issue as well and found this post. Elizabeth, your answer is close, you don't need to set the variable again. I tried running your example in python terminal and it clears out the variable "the_list" which is why it fails.
This is how you do it in one step. you wrap your pop with an insert.
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
messy_list.insert(0, messy_list.pop(3))
The order of operations will evaluate what is inside of the parenthesis first i.e., messy_list.pop(3), then it will execute the insert. I hope this helps. :)
Elizabeth Henning
4,286 PointsAnother badly written question in the Python courses. I'm new to Python, and I don't know how recursion works, so I just spent fifteen very frustrating minutes trying to figure out why my answers
the_list = the_list.insert(0, the_list.pop(3))
and
new_list = the_list.insert(0, the_list.pop(3))
the_list = new_list
weren't correct.
This question should be rewritten to say something like, "Create a new variable new_list ..."
Honestly, I'm fed up with how long it's taking me to get through this track because of these poorly written challenges. The next needless frustration I encounter like this is going to send me elsewhere.