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Dmitry Bruhanov
8,513 PointsPython collections - sets
I tried this code in a separate online consile. It returns the required result. However, the challenge keeps returning the Bummer! and Try again! Any ideas what is wrong with my code? What am I missing? Thanks in advance!
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(topics):
key = None
for key in COURSES.keys():
if topics & set(key.split()):
return [key]
2 Answers

Chris Freeman
Treehouse Moderator 68,094 PointsYou are headed in the right direction.
The phrase set(key.split())
creates a set from the key. This yields the sets {"Python", "Basics"}, {"Java", "Basics"}, etc. These will not properly compare with the submitted topics
.
Instead, you can compare the value retrieved with the key:
if topics & COURSES[key]:
The code needs to return a list of all courses that intersect with topics
Add a blank list that can be appended to when an intersection is found. Then return that list after the for loop
Post back if you need more help. Good luck!!

Dmitry Bruhanov
8,513 PointsThank you, I got it done:
def covers(topics):
topiclist = []
for key in COURSES.keys():
for value in COURSES[key]:
if value in topics:
topiclist.append(key)
return topiclist