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Python

Posted by John Michael
John Michael
1,239 Points

Python Exception TypeError

Hello Everyone,

I am trying to implement an exception into my code that when there is a TypeError, which appears when trying to use and int, it will print ("this is not a string") I have tried using the except TypeError: return print ("this is not a string") but that doesn't work either.

def eCount (s):

    count = 0
    for index in s:
        if index == 'e':
            count = count + 1
        elif index == 'E':
            count = count + 1
        # elif type(s) != str:
        #     print("This is not a nummber")
    return count
except TypeError as e:
    return print("This is not a string")

print (eCount ('Every e please.')) # should return 5
print (eCount (""))
print (eCount (5)

Thank you for the help!

nikolaiorenstrakh
nikolaiorenstrakh
280 Points

You return from eCount before getting to except return count , there is no try before except, except is out of eCount function body. You shouldn't print return , just print is enough

1 Answer

nikolaiorenstrakh
nikolaiorenstrakh
280 Points
nikolaiorenstrakh
nikolaiorenstrakh
280 Points

You return from eCount before getting to except return count , there is no try before except, except is out of eCount function body. You shouldn't print return , just print or return is enough