Justin Armstrong3,702 Points
I don't understand what I am doing wrong
def is_odd(number): if not number / 2: return True
I wrote it out with a decision structure that looked like
# pseudocode: if myNumber is even: return False else: return True
Maybe I'm finicky but I like to be able to explicitly return either True OR False, so I like to get that else statement in there.
That could just be me being inelegant, though.
Your test should involve the modulo operator. The test for even or odd qualities of a number comes down to the remnant after you do division by 2, (i.e. it comes down to NUMBER modulosymbol TWO...does that produce zero or not?)
Robin Goyal4,578 Points
So if your function is checking if a number is odd, you are just missing a few things but very close!
Right now, the line
not number / 2 will evaluate to true or false depending on the value of number. Recall the truthyness and falsyness of values. For numbers, 0 evaluates to False and anything that is not 0 is True. Therefore, if
number is equal to 6, then 6/2 is 3 and
not 3 would therefore be True and if your function would then return True even though 6 is an even number.
The modulus operator (%) gives the remainder for an operation
10 % 3 returns 1. Try to use modulo to determine if a number is a remainder or not.
Also, your function is returning True but also remember to return False in case a number is not odd. I hope this guides you to the right solution!