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# Python: How change half of a string

```def sillycase(stringArg):
lower = stringArg.lower()
# upper: somehow upper the second half the string, how do you make that determination?
# I can only see ways to change a specific character.
```

You need to get length of the stringArg, divide it by 2 and then use that number to begin or end replacing letters with upper or lowercase.

If you're stuck, here is the code:

```def sillycase(stringArg):
length = len(stringArg)/2
return stringArg[0:round(length)].lower() + stringArg[round(length):].upper()
```

Bummer! Where's `sillycase()`?

^^ The browser compiler returns that.

I've updated the code, made a typo in return. Try with this one.

Hey akak, I was not sure whether you original used "string" in the return statement for something else.

When you use the 0 in the first part of the return: stringArg[0:round(length).lower() > does the interpreter just know that is the first half?

Thanks.

Yeah, I wrote string everywhere at first and did not change it to stringArg.

As for the question. stringsArg[0:round(length)] means: take string from the beginning (0 means beginning of the string) until half of the sting. We know where the half is because we took the length of the string and split in half line earlier.

So if you take word "mystring" the length of it is 8. The half of it is 4. We lower the letters from beginning till 4 and then from 4 till end of the string. And we get "mystRING".