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Python

Oziel Perez
Oziel Perez
61,321 Points
Posted by Oziel Perez
Oziel Perez
61,321 Points

Python html macro not working

I'm absolutely stumped, I tried everything I could for this exercise. I have to turn "test@example.com" into "t***@example.com". It says to use a string split and a for loop, which I did use along with list() and enumerate(). I tried to solve this in a python interpreter till I got the string how I wanted it to. So then I put the code in macro syntax and I don't get anything. On top of that, the error says "Try again!" (that is so vaaague). What could I be doing wrong?

lunch.py 
from flask import Flask, render_template

app = Flask(__name__)

@app.route('/')
def index():
    class User:
        email = None
    user = User()
    user.email = 'test@example.com'
    return render_template('user.html', user=user)
templates/macro.html 
{% macro hide_email(user) %}
    {% email = user.email.split("@") %}
    {% email[0] = list(email[0]) %}
    {% for indx, chr in enumerate(email[0]) %}
        {% if indx > 0 %}
            {% email[0][indx] = "*" %}
        {% endif %}
    {% endfor %}
    {% email[0] = "".join(email[0]) %}
    {% email = "@".join(email) %}
    {{ email }}
{% endmacro %}

1 Answer

jacinator
jacinator
11,936 Points

This one stumped me for quite a while as well. This code passes the challenge.

  1. Print the first letter
  2. Take the first half of the email split on @ and then slice it the first letter out. For every character in that string print *
  3. print @
  4. print the second half of the email split on @

It is rather vague and easily messed up.

{% macro hide_email(user) %}
  {{ user.email[0] }}{% for char in user.email.split('@')[0][1:] %}*{% endfor %}@{{ user.email.split('@')[1] }}
{% endmacro %}
Oziel Perez
Oziel Perez
61,321 Points
Oziel Perez
Oziel Perez
61,321 Points

I tried it and it didn't work, it actually spits out "got t***@example.com" (which is supposed to be correct) and somehow it's still wrong. You think I should report this as a bug?

Oziel Perez
Oziel Perez
61,321 Points
Oziel Perez
Oziel Perez
61,321 Points

never mind it worked. I guess maybe my old answer was cached and still being used, who knows. Thanks!

jacinator
jacinator
11,936 Points

The one thing that I noticed was keeping it on one line. The code seemed to pick up the line breaks.