Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Python Iterable

I have a question that goes "Make a function named first_4 that accepts an iterable as an argument and returns the first 4 items in the iterable." and am stuck on what to do. How do I make the iterable?

you can try this

def man(iterable): return iterable[:4]

this will take an argument which is iterable and return the first four values of that iterable

Thank worked, thank you!

MOD

In iterable is anything that can be iterated upon. Such as a list, str, tuple. See docs: iterable

If you just want the first for items you can use the indexing `[:4]`, such as:

```In [8]: tup = (1, 2, 3, 4, 5, 6)

In [9]: tup[:4]
Out[9]: (1, 2, 3, 4)
```

If you want to use a function:

```In [10]: def first_4(iterable):
....:     return iterable[:4]
....:

In [11]: first_4(tup)
Out[11]: (1, 2, 3, 4)
```

You could also create a for-loop and inspect each item if you need operate on each item individually:

```In [15]: def first_4(iterable):
for item in range(4):
# operate on item
print(iterable[item])
....:

In [16]: first_4(tup)
1
2
3
4
```

Hi Larissa,

That's describing what kind of data will be passed to your function. So, your function will receive an iterable object, which means you can put it in a loop and look at each element.

```my_list = [1, 2, 3]  # this is an iterable

# function with a silly name that accepts one argument - which I am choosing to call itr, for iterable
def foo(itr):
for element in itr:
# lets see what's inside itr!
print(element)
```

Hope this helps!

Cheers

This is what I entered, but it isn't working: first_4 = (1, 2, 3, 4, 5)

first_4 [:4]

There should not be a space in between: `first_4[:4]`, but the interpreter is flexible:

```first_4 = (1,2,3,4,5)

In [18]: first_4 [:4]
Out[18]: (1, 2, 3, 4)

In [19]: first_4[:4]
Out[19]: (1, 2, 3, 4)
```

It still says it's incorrect, but it just says try again, so I don't know how I should change it

Can you post what you have entered and the error message given back. Sometimes it's the line above that causes the error.