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Thadeus Gordon
550 PointsPython list variables help
I don't know what I'm doing wrong.
available = "banana split;hot fudge;cherry;malted;black and white".split(;)
sundaes.join('available')
1 Answer
Chris Evergreen
2,857 PointsThe Cavalry's Here!
Hi there!
Alright, it's asking you to create a new variable called sundaes which holds the contents of available after you split it with .split().
Here's the first error. .split(;) is confused because ; is not a set variable or a string, so it doesn't know what to do. You can fix this by adding quotation marks around the semicolon to make it a string. That would give you .split(";"). But, we would also want to make that new variable, so make a new variable called sundaes and give it the split version of available. However, don't split available in the available variable; it would only give you a "bummer" response. Do it in the sundaes variable.
An example .split() of this at work would be:
random_string = "elephants.don't.grow.on.trees"
split_string = random_string.split(".")
And that would split it on every dot.
Hope this helps. Best of luck!