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Roland Ferrao
348 PointsPython lists
In the below list problem when I run the scrip and write the first item e.g. milk on the shopping list it give me the below error. Thoughts? NameError: name 'milk' is not defined
shopping_list = list() print("what should we pick up at the store?") print("Enter 'DONE' to stop adding items")
while True: new_item = input("> ") if new_ietm == 'DONE': break
shopping_list.append(new item) print("Added: List has {} items.".format(len(shopping_list)))
print("Here is your list:")
for item in shopping_list:
print(item)
6 Answers
Luke Glazebrook
13,564 PointsHi Roland!
You have a typo in your conditional statement! Try correcting that and seeing if it solves your problem!
-Luke
Roland Ferrao
348 PointsNot sure what the error is? Could you please assist? The 'continue' keyword in the original script is not needed which is why I removed it. On another note I am using version 2.7. Does that make a difference?
Luke Glazebrook
13,564 PointsHi Roland! Did you fix the typo?
It may make a difference yes. You should really be writing in Python 3.4 if you are wanting to follow along closely with the Python course.
Kenneth Love
Treehouse Guest TeacherOn any Python lower than 3.0, use raw_input() instead of input(). Just one of the many reasons we're using Python 3 instead of 2.
Roland Ferrao
348 PointsAh works like a charm. Just updated to the latest version of Python. Thanks to both.
Roland Ferrao
348 PointsWhen I check the below code from challenge on shopping lists in the Python interepreter it works fine. However in the workspace it says there is an error. Thoughts?
full_name = "Roland Ferrao" name_list = full_name.split() greeting_list = "Hi, I'm X".split() greeting_list = "Hi, I'm {}".format(name_list[0])
Joey Barter
1,261 PointsHi Roland, The challenge wants you to return something that has been constructed from the two lists, not just typed as a string. Almost there. Try;
greeting_list[2] = name_list[0] greeting = " ".join(greeting_list) print(greeting)
Roland Ferrao
348 PointsThanks Joey.