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# python not working or pass the test

That one wasn't too bad, right? Let's try something a bit more challenging. Create a new function named num_courses that will receive the same dictionary as its only argument. The function should return the total number of courses for all of the teachers.

def num_teacher(course): return len(course)

num_teacher(course)

total_num = [] def num_courses(course): for teacher in course: num_course = len(course[teacher]) total_num.append(num_course) total_num_course = sum(total_num) return total_num_course

num_courses(course)

teachers.py
```# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teacher(course):
return len(course)

total_num = []
def num_courses(course):
for teacher in course:
num_course = len(course[teacher])
total_num.append(num_course)
total_num_course = sum(total_num)
```

The solution is as follow:

1. Take the dictionary in the function
2. loop over each teacher
3. Do a lookup in the dictionary with the teacher's name
4. Get the length of the lookup(courses array) as it denotes the number of courses
5. Accumulate the number of courses in the count variable to add all of the courses
6. Return the count
```def num_courses(teachers_dict):
count = 0
for teacher in teachers_dict:
count = count + len(teachers_dict[teacher])

return count
```