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Mark Kohner
1,760 PointsPython: Number game takeaways, extra Reverse number game logic problems
I found the problem of making a 'reverse' number game interesting, and I am able to get it to mostly work but through sloppy code that is tedious to make. I imagine there is some elegant solution that I am very curious to see!
import random computer_guess = random.randint(1, 20)
now when the computer makes a random guess, and it takes input of too high or too low;
user_choice = input()
ie we choose 10
if the computer guesses 11, we input 'lower', here is where my issue comes in.
How can we format the code so that it loops through and limits the ranges of choices?
if answer.lower() == 'low':
# answer will have to be higher
print("I will guess higher next time.")
second_choice = random.randint(number, 20)
if answer.lower() == 'high':
# next answer has to be lowered
print("I will guess lower next time.")
second_choice = random.randint(1, number)
this gets the range lowered appropriately, but I do not see how to work this into a loop. It resets if typed repeatedly. How to narrow the range in a loop with each guess until an accurate guess is achieved?
2 Answers
Steven Parker
231,269 Points
Narrowing the range is just a matter of retaining both limits.
Based on the user's input each time through the loop, you can update either the low limit or the high limit for the next pick:
if answer.lower() == 'low':
# answer will have to be higher
print("I will guess higher next time.")
lownum = computer_guess + 1
if answer.lower() == 'high':
# next answer has to be lowered
print("I will guess lower next time.")
highnum = computer_guess - 1
# pick the next guess within the new range
computer_guess = random.randint(lownum, highnum)
