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Python

Posted by Florian Benkö
Florian Benkö
2,766 Points

python search numbers in list

i did this excercise at codingbat. it does work, but i am assuming something like a "list out of index" because the end slice part will point to like len(nums)+5

Given an array of ints, return True if .. 1, 2, 3, .. appears in the array somewhere.

array123([1, 1, 2, 3, 1]) → True

array123([1, 1, 2, 4, 1]) → False

array123([1, 1, 2, 1, 2, 3]) → True

def array123(nums):
  wisdom = False

  for num in range(len(nums)+2):
    if nums[num:num+3] == [1, 2, 3]:
      wisdom = True
  return wisdom

2 Answers

Steven Parker
Steven Parker
243,134 Points
Steven Parker
Steven Parker
243,134 Points

I would think you would SUBTRACT two from the range limit, since you can no longer extract 3-item slices once you pass that point.

  for num in range(len(nums) - 2):

Perhaps the "+" sign was just a typo?

Florian Benkö
Florian Benkö
2,766 Points
Florian Benkö
Florian Benkö
2,766 Points

thank you for your answer, yes if something -2 makes more sense. tough today i found out slicing is very cool, it never throws out of index.

>>>  str = "h"
>>>  str[:20]
 'h'

its bad to do something like this?