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Alec Sandoval
1,687 Pointspython squaring function
I am having trouble with the syntax of writing a function
def squared(num):
num = int(input("enter number "))
print(num*num)
squared(num)
I tried running this on the console of workspaces and I was told that "num is not defined" I realized it was only defined inside of the function and maybe that is why I was getting error. how do I fix this
1 Answer
Michael Hulet
47,913 PointsYou have 2 problems here. Yes, you're right about num not being defined when you call it. It's a function parameter, so it's only available in that function. When you call a function, you need to pass it an actual value (or a variable that contains one), so a number literal would work best here. Second of all, you probably shouldn't call input. Judging by the context, it seems like you should be operating on num directly instead of calling input and reassigning num
Alec Sandoval
1,687 PointsAlec Sandoval
1,687 PointsThank you. That makes sense