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Python

BOHAN ZHANG
BOHAN ZHANG
4,446 Points

Python Stuck

That one wasn't too bad, right? Let's try something a bit more challenging. Create a new function named num_courses that will receive the same dictionary as its only argument. The function should return the total number of courses for all of the teachers.No clue why my function does not work foe the second question, the out put is correct on my local https://teamtreehouse.com/library/python-collections-2/dictionaries/teacher-stats

code

teachers = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],  'Kenneth Love': ['Python Basics', 'Python Collections']}
def num_teachers(teachers):
    count = 0
    for d in teachers.keys():
        count = count+1
    return count


num_teachers(teachers) 

def num_courses(teachers):
    count = 0
    a = teachers.values()
    my_list2, my_list1 = zip(*a)
    list_total = my_list2 + my_list1
    for d in list_total:
        count = count + 1
    return counnt

num_courses(teachers)

1 Answer

Steven Parker
Steven Parker
229,732 Points

:warning: Be careful about testing a challenge in an external REPL.
The actual test data will almost certainly not be the same as the sample shown in the instructions.

This line in particular struck me as extremely "brittle":

    my_list2, my_list1 = zip(*a)

What if the actual argument has different numbers of classes for each teacher? And what if there are more than 2 teachers? Both of these are quite likely to be the case in the real test data.

Also, for the challenge you only need to define the functions, you don't need to call them (or define any global variables).