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Python

Kimmo Ojala
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.a{fill-rule:evenodd;}techdegree
Kimmo Ojala
Python Web Development Techdegree Student 8,257 Points

Python SyntaxError: invalid syntax

What is wrong with my code? I get a syntax error at row 19.

import random


def game():
    secret_num = 5
    cguess = random.randint(1, 10)
    cguesses = []

    while len(cguesses) < 5:
        if cguess == secret_num:
            print("You got it! My number was {}".format(secret_num))
            break  
        elif guess < secret_num:
            print("My number is higher than {}".format(guess))
        else:
            print("My number is lower than {}".format(guess))
    cguesses.append(cguess)

    else:
        print("You didn't get it! My number was {}".format(secret_num))
    play_again = input("Do you want to play again? Y/n ")
    if play_again.lower() != 'n':
        game()
    else:
        print("Bye!")

game() 

[MOD: added ```python formatting -cf]

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points

The line cguesses.append(cguess) closes the while loop code block. Then the else has no associated if, while, for, or try loop. This causes the syntax error.