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C# Querying With LINQ Query Operators Partitioning

Posted by Joe Shaw
Joe Shaw
10,910 Points

Querying with Linq - Partitioning Challenge 2/2

Hello , I have been beating my head against this for some time and getting very frustrated. I keep getting the error that my nextThreeBirds variable cannot contain birds from my firstThreeBirds variable but the code seems to be find. PLEASE HELP.

CodeChallenge.cs 
var birds = new List<Bird>
{
    new Bird { Name = "Cardinal", Color = "Red", Sightings = 3 },
    new Bird { Name =  "Dove", Color = "White", Sightings = 2 },
    new Bird { Name =  "Robin", Color = "Red", Sightings = 5 },
    new Bird { Name =  "Canary", Color = "Yellow", Sightings = 0 },
    new Bird { Name =  "Blue Jay", Color = "Blue", Sightings = 1 },
    new Bird { Name =  "Crow", Color = "Black", Sightings = 11 },
    new Bird { Name =  "Pidgeon", Color = "White", Sightings = 10 }
};

var firstThreeBirds = birds.Take(3);

var nextThreeBirds = birds.OrderBy(b => b.Name.Length).Skip(3).Take(3);

4 Answers

Steven Parker
Steven Parker
229,785 Points
Steven Parker
Steven Parker
229,785 Points

:point_right: Don't re-order the list.

By changing the list order, your "next" three birds are not completely different from your "first" three.

Just get rid of the "OrderBy" — the challenge did not ask for that anyway.

Terry McDuffie
Terry McDuffie
12,786 Points
Terry McDuffie
Terry McDuffie
12,786 Points

var birds = new List<Bird> { new Bird { Name = "Cardinal", Color = "Red", Sightings = 3 }, new Bird { Name = "Dove", Color = "White", Sightings = 2 }, new Bird { Name = "Robin", Color = "Red", Sightings = 5 }, new Bird { Name = "Canary", Color = "Yellow", Sightings = 0 }, new Bird { Name = "Blue Jay", Color = "Blue", Sightings = 1 }, new Bird { Name = "Crow", Color = "Black", Sightings = 11 }, new Bird { Name = "Pidgeon", Color = "White", Sightings = 10 } };

var firstThreeBirds = birds.Take(3);

var nextThreeBirds = birds.Skip(3).Take(3);

Sara Rena Anderson
Sara Rena Anderson
15,045 Points
Sara Rena Anderson
Sara Rena Anderson
15,045 Points 
var birds = new List<Bird>
{
    new Bird { Name = "Cardinal", Color = "Red", Sightings = 3 },
    new Bird { Name =  "Dove", Color = "White", Sightings = 2 },
    new Bird { Name =  "Robin", Color = "Red", Sightings = 5 },
    new Bird { Name =  "Canary", Color = "Yellow", Sightings = 0 },
    new Bird { Name =  "Blue Jay", Color = "Blue", Sightings = 1 },
    new Bird { Name =  "Crow", Color = "Black", Sightings = 11 },
    new Bird { Name =  "Pidgeon", Color = "White", Sightings = 10 }
};
var firstThreeBirds = birds.Take(3);
var nextThreeBirds = birds.Skip(3).Take(3);
Kevin Gates
Kevin Gates
15,052 Points
Kevin Gates
Kevin Gates
15,052 Points

Your solution provides an "OrderBy" but the question didn't ask for that. It is only needing to skip the first 3 before you take the next 3.

var birds = new List<Bird>
{
    new Bird { Name = "Cardinal", Color = "Red", Sightings = 3 },
    new Bird { Name =  "Dove", Color = "White", Sightings = 2 },
    new Bird { Name =  "Robin", Color = "Red", Sightings = 5 },
    new Bird { Name =  "Canary", Color = "Yellow", Sightings = 0 },
    new Bird { Name =  "Blue Jay", Color = "Blue", Sightings = 1 },
    new Bird { Name =  "Crow", Color = "Black", Sightings = 11 },
    new Bird { Name =  "Pidgeon", Color = "White", Sightings = 10 }
};

var firstThreeBirds = birds.Take(3);
var nextThreeBirds = birds.Skip(3).Take(3);