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Java

Posted by Derek Markman
Derek Markman
16,291 Points

Question about costructors

Consider the following code:

class ConstructorExample {
  ConstructorExample() {
  System.out.println("random text blah....");
}
}

Even though I have a simple println statement inside my constructor does the compiler, by default, still add the call to super(); before my println statement?

1 Answer

Pedro Cabral
.a{fill-rule:evenodd;}techdegree
Pedro Cabral
Full Stack JavaScript Techdegree Student 23,916 Points

Yes, it does. You can test it with some code like this

class A {
  A() {
    System.out.println("A being created."); 
  }
}

class B extends A {
  public B() {
    System.out.println("B being created.");
  }
}

public class Application {
  public static void main(String[] args)  {
    B b = new B();
  }
}

which will return:

A being created.
B being created.
Derek Markman
Derek Markman
16,291 Points

@Pedro Cabral thanks for clearing that up man. I thought it did I just had to make sure.