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PHP PHP Functions Introducing Functions PHP Function Arguments

gabriel wambua
gabriel wambua
5,061 Points

Question about function arguments why did the teacher not use $arr as the array?

Hi guys,

I have a question about functions and arrays based on the following code


function hello($arr){

//why $arr and not the name of the actual array name???!!

if(is_array  ($arr)){
       foreach($arr as $name){
          echo "Hello $name </br>" ;
 } else {
   echo "This is not an array";



$namesinarray= array ( 'Joseph', 'Brian', 'James' );

//Why didn't we use $arr here????? //Also why didnt we declare $namesinarray as global???



Thanks for helping

1 Answer

Steven Parker
Steven Parker
229,982 Points

A parameter name ("$arr" in this case) acts as a placeholder for the actual argument. There's no technical advantage to having be the same as the argument that will be passed in the actual call, and it can sometimes make the code confusing to read if it is.

Naming the actual array "$arr" would potentially cause the same confusion between the value and the parameter. And "$namesinarray" is only being used within the scope it is created in.