Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Java Java Basics Perfecting the Prototype Censoring Words - Looping Until the Value Passes

Question about isInvalidWord variable.

I noticed the code in the video is:

isInvalidWord = (noun.equalsIgnoreCase("dork") || noun.equalsIgnoreCase("jerk"));

with parenthesis around the value. So, in the "if ()" statement, it would be:

if ( (noun.equalsIgnoreCase("dork") || noun.equalsIgnoreCase("jerk")) )

Is that correct? I tried removing the outer parenthesis when defining isInvalidWord and the code worked the same. So do extra parenthesis not matter? Could I write:

if (((((noun.equalsIgnoreCase("dork") || noun.equalsIgnoreCase("jerk"))))))

and it would still work?

27,258 Points

yes, as long as you have the same number of opening and closing parentheses.

rdaniels ok, thank you!