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Question about java/android logic.

I'm currently trying to create a countdown timer for a project of mine. It is working but I was just trying to understand one part.

 private void startStop() {
        } else {

For some context, timerRunning is a boolean that's set to its default (which is false). The startstop method is a method for used in a onclick method for a button.

So the code says "If false stop timer. Else (if true) start timer".

So if the code by default is false how can it start the timer?

4 Answers

Hi Yusuf,

The code will work as you describe.

So if the code by default is false how can it start the timer?

If timerRunning is set to false by default, the else clause will run. The else clause calls the funtion startTimer() which, presumably, makes the time start!

 private void startStop() {
            stopTimer(); // this won't run if timerRunning is false
        } else {
            startTimer(); // but this will run so your timer will start
} // I added this

I hope that helps.


Okay so when the value is false, that's when the else clause will run.

Wouldn't the logic be if timer is running (timerRunning = true) stop timer? How do you stop the timer if it isn't running? It is already stopped.

That's the problem I'm not understanding, it shouldn't work the way I'm doing it but the timer is working so idk if there's something we're missing.

Bumpidity bump.

Hi Yusuf. Actually, your code reads "if true, stop timer, else, start timer", so it works perfectly.


 if (timerRunning){
 // (..)

is the same as writing

 if (timerRunning == true) {
 // (...)

I know it's confusing at first.

By the way, if you'd like to check if a Boolean has a value of false, just write

 if (! timerRunning) {. // Instead of (timerRunning == false)
 // (...)

Hope that helps :)