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JavaScript JavaScript Loops, Arrays and Objects Tracking Multiple Items with Arrays Two-Dimensional Arrays

Question about the parameter's name being repeated throughout its function

I was wondering this too. I get what you are saying about the parameter being a placeholder and that from the "perspective" of the computer the name of the parameter is unimportant. What I still don't quite understand is how this code runs properly even though the parameter name is repeated throughout the loop. For example in

function printSongs( songs ) {
  var listHTML = '<ol>';
  for ( var i = 0; i < songs.length; i += 1) {
    listHTML += '<li>' + songs[i][0] + ' by ' + songs[i][1] + '</li>';
  }
  listHTML += '</ol>';
  print(listHTML);
}

we have "songs.length," "songs[i][0]," etc. I would think at least these would need to say "playList.length" or "playList[i][0]," yet the code runs fine.

My question is, would it be accurate to say that when an argument is passed to a function, any time the parameter's name is repeated throughout the duration of the function, the computer treats it as though the parameter's name is that of the argument until the function ends?

2 Answers

Steven Parker
Steven Parker
229,608 Points

Your "question" is spot on — it sounds like you understand the concept exactly. :+1:

And it's important that the parameter name is used consistently within the function and not the argument name, so that the function will perform correctly when it is called with a different argument.

Kate C
Kate C
13,589 Points

In this workspace, there is function print(message) and also printSongs (playList) , which seem doing the same thing? Plus, function printList(songs).....

I am still thinking why we need so many parameters.....If parameters are not that important since argument is doing the thing. Also, from previous workspace of the same playlist example, there is function print(html) {document.write(html);}

Steven Parker
Steven Parker
229,608 Points

Parameters are very important, and arguments cannot be used without them.